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POJ 2578 Keep on Truckin'(我的水题之路——谁先大于168)
阅读量:4069 次
发布时间:2019-05-25

本文共 1905 字,大约阅读时间需要 6 分钟。

Keep on Truckin'
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 7166   Accepted: 5374

Description

Boudreaux and Thibodeaux are on the road again . . . 
"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!" 
"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!" 
"We're not going to make it, I say!" 
So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description. 
The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

Output

There will be exactly one line of output. This line will be: 
NO CRASH 
if the height of the 18-wheeler is less than the height of each of the underpasses, or: 
CRASH X 
otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler). 
The height of the 18-wheeler is 168 inches. 

Sample Input

180 160 170

Sample Output

CRASH 160

Source

给三个数字,从左到右,看哪个数字先大于168(
The height of the 18-wheeler is 168 inches. )。
水算法。。
代码(1AC):
#include 
#include
#include
int main(void){ int a, b, c; while (scanf("%d%d%d", &a, &b, &c) != EOF){ if (a <= 168){ printf("CRASH %d\n", a); } else if (b <= 168){ printf("CRASH %d\n", b); } else if (c <= 168){ printf("CRASH %d\n", c); } else{ printf("NO CRASH\n"); } } return 0;}

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